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Tuesday 26 May 2020

Maths Challenge #2


LI: to find the most efficient strategy to solve the math's problem.

For the maths challenge for this week we had to do a lot of multiplication and skip counting, so the question was for every hour they get 3 fish, they also had one extra fish, so in a hour they'd get 2 fish, in two hours they'd get 5 fish, and in 3 hours they'd get 8 and so on. We had to find out how many fish they would get in 6 hours, 10 hours, 20 hours and 100 hours.

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